25c^2-80c+64=

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Solution for 25c^2-80c+64= equation:


Simplifying
25c2 + -80c + 64 = 0

Reorder the terms:
64 + -80c + 25c2 = 0

Solving
64 + -80c + 25c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(8 + -5c)(8 + -5c) = 0

Subproblem 1

Set the factor '(8 + -5c)' equal to zero and attempt to solve: Simplifying 8 + -5c = 0 Solving 8 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -5c = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -5c = 0 + -8 -5c = 0 + -8 Combine like terms: 0 + -8 = -8 -5c = -8 Divide each side by '-5'. c = 1.6 Simplifying c = 1.6

Subproblem 2

Set the factor '(8 + -5c)' equal to zero and attempt to solve: Simplifying 8 + -5c = 0 Solving 8 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -5c = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -5c = 0 + -8 -5c = 0 + -8 Combine like terms: 0 + -8 = -8 -5c = -8 Divide each side by '-5'. c = 1.6 Simplifying c = 1.6

Solution

c = {1.6, 1.6}

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